ZTP using for Poly VVX Series phones

[Taikc]

Hi 

Can I know if anyone has issues today for doing ZTP for Poly phone VVX Series for Zoom Phone?

I have issues that the Poly phone did not upgrade to the supported firmware/software version.

The provision path is https://provpp.zoom.us ...

[Eliot · Accepted solution]

hi taikc,

 which vvx model and revision do you have? 

What firmware version do you get when you use ztp?

VVX 250/350/450 come with two firmware versions depending on the hardware revision (Old or New). Please review the Poly Product Shipping Configuration Change Notice for more detailed information about new hardware revisions.

VVX 250 Business IP Phone

AES-256

6.4.5.1210 (Old hardware rev) 6.4.5.1251 (New hardware rev)

5/28/2023 (see Note)

VVX 350 Business IP Phone

AES-256

6.4.5.1210 (Old hardware rev) 6.4.5.1251 (New hardware rev)

5/28/2023 (see Note)

VVX 450 Business IP Phone

AES-256

6.4.34.3178 (Old hardware rev) 6.4.5.1251 (New hardware rev)

5/28/2023 (see Note)

https://support.zoom.us/hc/en-us/articles/360001299063-Zoom-Phone-Certified-Hardware#

Did my response answer your question? If so, please don't forget to mark the reply as an accepted solution.

thanks,  eliot

[Taikc]

Hi Eliot

Thanks for the advise. I am working with VVX411. It is the same firmware version used. Currently out company is deploying 6.4.5.1210.

[Eliot]

hi taikc,

i tried with one of my vvx411 that i had not used since april 2023.  when i plugged it in, the vvx411 it automatically upgraded firmware to 6.4.5.1210.  i removed the vvx411 from my account.  i did a factory reset and then added the vvx411 back in.  everything worked as expected.

VVX 411 Business Media Phone	AES-256	6.4.5.1210	5/28/2023

Zoom Phone Certified Hardware – Zoom Support

Before rebooting poly vvx 411 had 6.4.4.3178.

After rebooting poly vvx411 had 6.4.5.1210

Removed vvx411, did a factory reset, added vvx411 to unassigned devices and then assigned to user.  Everything worked and had 6.4.5.1210.

maybe zoom or poly fixed something?

thanks,  eliot